Two.Sigma

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Run #764

done rubric v1 session 79434690 gemini-3.7-flash 2026-09-21 02:21
Session in Sessions →

The recording

What the student sent the question as it arrived, then each reading of it

OCR of the image GOOGLE_VISION

प्रमेय 6.1 [थेल्स प्रमेय / आधारभूत समानुपातिकता प्रमेय) यदि किसी नियाल की एक अना के बराबर समांतर अन्य दो भुजाओं को भिन्न-भिन्न बिंदुओं पर प्रतिच्छेद करने "के लिए एक रेखा खींची जाए, तो ये अन्य दो सुनाएँ एक ही अनुपात में विभाजित हो जाती है।

The phone's own reading, which differs:

হक ही ुपत में विभाजत रे वाती বি, लिशु , ২खा वখ আহ। तू दो हुं वो बन्িন্ বহ प पম शन्य द यदे मसी ফ ी ूসা ब ানয সप ी हुर किख की जमेय ेट्श प्रमेश সসू सभातुपातिज प्रमष

The audit's reading of the question, which is what the Product AI judged against:

प्रमेय 6.1 [थेल्स प्रमेय / आधारभूत समानुपातिकता प्रमेय) यदि किसी नियाल की एक अना के बराबर समांतर अन्य दो भुजाओं को भिन्न-भिन्न बिंदुओं पर प्रतिच्छेद करने

Audit's summary: The student asked for a proof of Thales' theorem (Basic Proportionality Theorem). The tutor explained the theorem and then proceeded to prove it using a step-by-step approach. The tutor drew a triangle ABC with DE parallel to BC and constructed perpendiculars EM and DN. The tutor calculated the areas of various triangles and used ratios to prove that AD/DB = AE/EC. The tutor also highlighted the property that triangles on the same base and between the same parallels have equal areas. The session was conducted primarily in Hindi with some English terms used.

Transcript 2,101 characters · 105 stripped

Read it no speaker labels — tutor and student run together

Hello, Welcome to Filo. What language are you speaking? Hindi or English? Hindi. Okay, okay. If you want to compare two different sounds of a certain language, then you can do so. This is your cell serum. So triangle ABC is given. D is parallel to BC. So we have to prove that D is parallel to BC. AD upon DB equal to AE upon EC. आप दोखों रशना क्या करनी है? रशना में दोखों आपको क्या करना है? BE को मिलाना है और CD को मिलाना है. BE तथा CD को मिलाया. Now what to do? EM perpendicular is to be drawn and DN perpendicular is to be drawn. So EM is perpendicular to AB and DN is perpendicular. So, Area of Triangle ADE, Half Base AD and Height EM. Then we will talk about Area of Triangle DEB. If you are able to see DEB, then this is DEB. इसके लिए बेस हो जाएगा half एक्वाटियार, half ठीक है, बीडी और यह height एम सेम हो जाएगी, ठीक है, तो इन दोनों को आपस में कर देंगे, divide, equation first और second को, तो area of triangle ADE upon area of triangle DEB, ठीक है, तो यह हो जाएगा AD upon BD, कोई दिक्कत समस्या, The following is the same. We will apply the same method in this too. Area of triangle. ADE. We will write it again. Now here the base will be AE. And the height will be DN. Now we will take the triangle from here. Now we will take this triangle here. Thank you for watching. एरिया ट्राइंगल DEC आपका बेस एसी रहेगा और हाइट डी आँए रहेगे तो अब इसको मालने थे एक्वेशन ठीक है यह तीन हो गई यह एक्वेशन हो गई चार और एक्वेशन हो गई पांच So, equation 4 divided by equation 5. Okay? Area of triangle ADE. Area of triangle DEC. Now, see. This half will be cancelled out from half. If DN goes from DN, then AE upon EC. Any problem? Okay? This is what you will learn here. The following is the case when two parallel lines have the same area between the triangles. The following is the definition of the area of triangle DEEB. Area of triangle DEB equal to area of triangle DEC. Area of triangle ADE upon area of triangle DEC. The LHS of this one is equal to the LHS of this one. So, RHS will be the same. So, this is what we have to prove. Do you have any problem? Thank you for watching. Thank you for watching.

What the student sent the question as it arrived, then each reading of it

OCR of the image GOOGLE_VISION

प्रमेय 6.1 [थेल्स प्रमेय / आधारभूत समानुपातिकता प्रमेय) यदि किसी नियाल की एक अना के बराबर समांतर अन्य दो भुजाओं को भिन्न-भिन्न बिंदुओं पर प्रतिच्छेद करने "के लिए एक रेखा खींची जाए, तो ये अन्य दो सुनाएँ एक ही अनुपात में विभाजित हो जाती है।

The phone's own reading, which differs:

হक ही ुपत में विभाजत रे वाती বি, लिशु , ২खा वখ আহ। तू दो हुं वो बन्িন্ বহ प पম शन्य द यदे मसी ফ ी ूসা ब ানয সप ी हुर किख की जमेय ेट्श प्रमेश সসू सभातुपातिज प्रमष

The audit's reading of the question, which is what the Product AI judged against:

प्रमेय 6.1 [थेल्स प्रमेय / आधारभूत समानुपातिकता प्रमेय) यदि किसी नियाल की एक अना के बराबर समांतर अन्य दो भुजाओं को भिन्न-भिन्न बिंदुओं पर प्रतिच्छेद करने

Audit's summary: The student asked for a proof of Thales' theorem (Basic Proportionality Theorem). The tutor explained the theorem and then proceeded to prove it using a step-by-step approach. The tutor drew a triangle ABC with DE parallel to BC and constructed perpendiculars EM and DN. The tutor calculated the areas of various triangles and used ratios to prove that AD/DB = AE/EC. The tutor also highlighted the property that triangles on the same base and between the same parallels have equal areas. The session was conducted primarily in Hindi with some English terms used.

Transcript 2,101 characters · 105 stripped

Read it no speaker labels — tutor and student run together

Hello, Welcome to Filo. What language are you speaking? Hindi or English? Hindi. Okay, okay. If you want to compare two different sounds of a certain language, then you can do so. This is your cell serum. So triangle ABC is given. D is parallel to BC. So we have to prove that D is parallel to BC. AD upon DB equal to AE upon EC. आप दोखों रशना क्या करनी है? रशना में दोखों आपको क्या करना है? BE को मिलाना है और CD को मिलाना है. BE तथा CD को मिलाया. Now what to do? EM perpendicular is to be drawn and DN perpendicular is to be drawn. So EM is perpendicular to AB and DN is perpendicular. So, Area of Triangle ADE, Half Base AD and Height EM. Then we will talk about Area of Triangle DEB. If you are able to see DEB, then this is DEB. इसके लिए बेस हो जाएगा half एक्वाटियार, half ठीक है, बीडी और यह height एम सेम हो जाएगी, ठीक है, तो इन दोनों को आपस में कर देंगे, divide, equation first और second को, तो area of triangle ADE upon area of triangle DEB, ठीक है, तो यह हो जाएगा AD upon BD, कोई दिक्कत समस्या, The following is the same. We will apply the same method in this too. Area of triangle. ADE. We will write it again. Now here the base will be AE. And the height will be DN. Now we will take the triangle from here. Now we will take this triangle here. Thank you for watching. एरिया ट्राइंगल DEC आपका बेस एसी रहेगा और हाइट डी आँए रहेगे तो अब इसको मालने थे एक्वेशन ठीक है यह तीन हो गई यह एक्वेशन हो गई चार और एक्वेशन हो गई पांच So, equation 4 divided by equation 5. Okay? Area of triangle ADE. Area of triangle DEC. Now, see. This half will be cancelled out from half. If DN goes from DN, then AE upon EC. Any problem? Okay? This is what you will learn here. The following is the case when two parallel lines have the same area between the triangles. The following is the definition of the area of triangle DEEB. Area of triangle DEB equal to area of triangle DEC. Area of triangle ADE upon area of triangle DEC. The LHS of this one is equal to the LHS of this one. So, RHS will be the same. So, this is what we have to prove. Do you have any problem? Thank you for watching. Thank you for watching.

Review team

no_issue

Product AI

nothing found

teaching Yes · mistakes No · satisfactory Yes

Each verdict takes your own. Yours is stored against the stack's, so “where is it wrong most often” is a question with an answer.

  1. Work is the right way up Canvas and handwritten working are upright.
    The tutor's whiteboard notes, diagram, and mathematical equations are oriented at 0 degrees across Frames 2 to 8.
    seen · 95% confident
  2. Your view
  3. Writing is legible at video size The handwriting is clear, neatly color-coded, and easily readable.
    In Frames 2–8, the diagram, Hindi annotations, and mathematical proof equations are well-spaced with high contrast against the dark background.
    seen · 95% confident
  4. Your view
  5. The work fills the frame Not applicable to a board session
    seen
  6. Nothing distracting in shot Not applicable to a board session
    seen
  7. The student's problem is established The theorem image is clearly displayed at the top of the canvas.
    The statement of Thales Theorem / Basic Proportionality Theorem is visible at the top of the canvas in Frames 1–5.
    seen · 95% confident
  8. Your view
  9. Work proceeds in followable steps The mathematical proof is laid out logically in columns.
    Left side contains given/to prove, construction, and first ratio (Frames 2–5), while the right side contains the second area ratio and conclusion (Frames 5–8).
    seen · 95% confident
  10. Your view
  11. It reaches an answer The proof is completed by the end of the session.
    Frame 8 shows the full proof showing equality of areas and equating ratios to conclude the theorem.
    seen · 90% confident
  12. Your view
  13. Something was actually written board went from 11.32% to a peak of 12.62% covered (+1.30 points), ending at 6.09%
    Very little appeared on the board.
    measured
  14. Your view
  15. The concept is named before the working The tutor identifies the theorem being proved.
    The tutor names the theorem (transcribed as 'This is your cell serum' for Thales Theorem) and it is labeled as 'थेल्स प्रमेय' on the problem image.
    heard · 85% confident
  16. Your view
  17. Explained rather than jumped to the answer The tutor clearly defines what is given, to prove, and the construction before calculating areas.
    In Frames 2 and 3, given conditions, 'सिद्ध करना है', and construction lines are written and highlighted before calculating areas in Frame 4.
    heard · 90% confident
  18. Your view
  19. Solved step by step, not in one leap The theorem is proved step-by-step with visual annotations.
    Frames 3–8 demonstrate step-by-step progression: constructing perpendiculars, calculating areas of respective triangles, taking ratios, and concluding.
    heard · 95% confident
  20. Your view
  21. The session opens properly The tutor warmly greets the student and confirms language before starting.
    Transcript opens with 'Hello, Welcome to Filo. What language are you speaking? Hindi or English? Hindi. Okay, okay.'
    heard · 95% confident
  22. Your view
  23. No long dead air 5 gaps over 6.0s, 42s total (11% of the session), longest 13s
    Silence is below -35.0dB — a crude measure on a phone microphone, so treat a low count as weak evidence rather than proof the tutor was talking.
    measured
  24. Your view
Observations judged, but not counted as the lab objecting
  1. The camera holds still Not applicable to a board session
    Not counted: Measured over 183 known-bad and 29 known-good camera sessions (2026-09-21): raised on 87% of the bad and 86% of the good, and the motion distributions are the same shape — median frame difference 25 on the bad set, 27 on the good. No threshold on this number separates them, so it is reported and not counted.
    measured
  2. Exposure is usable Not applicable to a board session
    Not counted: Same two sets: it raised 6 of 183 known-bad and 2 of 29 known-good sessions. Both too few to mean anything, and the brightness distributions overlap almost exactly. The earlier reading that it 'fires more on clean sessions' was two sessions out of twenty-nine — noise, not an inverted rule.
    measured
  3. Understanding of the concept is checked Only comprehension check phrases were asked without probing conceptual questions.
    The tutor asks superficial questions like 'कोई दिक्कत समस्या' and 'Any problem?' throughout the transcript rather than checking conceptual understanding.
    Not counted: Raised on 87% of known-bad and 80% of known-good sessions. The criterion is honest about why in its own `why`: the transcript has no speaker labels, so a real check and a rhetorical 'ok?' are often indistinguishable, and the bar ends up one almost no session clears. Still judged and shown, because reading it beside a recording is how it gets better.
    heard
  4. Your view

Measured

Duration361s (6.0 min)
Video1280×800 @ 10.0fps
Audio trackyes
Shot changes
Dead air5 gaps ≥6.0s · 41.5s total · longest 13.0s
Lumaavg 47.7 · min · max
Mediumboard 88.2% flat background
Content written11.32% → 6.09% (+1.3)
Transcript 2101 characters of speech
Frames8

What the model returned verbatim

{
  "findings": [
    {
      "key": "orientation",
      "verdict": "ok",
      "headline": "Canvas and handwritten working are upright.",
      "evidence": "The tutor's whiteboard notes, diagram, and mathematical equations are oriented at 0 degrees across Frames 2 to 8.",
      "confidence": 0.95
    },
    {
      "key": "legibility",
      "verdict": "ok",
      "headline": "The handwriting is clear, neatly color-coded, and easily readable.",
      "evidence": "In Frames 2–8, the diagram, Hindi annotations, and mathematical proof equations are well-spaced with high contrast against the dark background.",
      "confidence": 0.95
    },
    {
      "key": "question_captured",
      "verdict": "ok",
      "headline": "The theorem image is clearly displayed at the top of the canvas.",
      "evidence": "The statement of Thales Theorem / Basic Proportionality Theorem is visible at the top of the canvas in Frames 1–5.",
      "confidence": 0.95
    },
    {
      "key": "structure",
      "verdict": "ok",
      "headline": "The mathematical proof is laid out logically in columns.",
      "evidence": "Left side contains given/to prove, construction, and first ratio (Frames 2–5), while the right side contains the second area ratio and conclusion (Frames 5–8).",
      "confidence": 0.95
    },
    {
      "key": "completion",
      "verdict": "ok",
      "headline": "The proof is completed by the end of the session.",
      "evidence": "Frame 8 shows the full proof showing equality of areas and equating ratios to conclude the theorem.",
      "confidence": 0.9
    },
    {
      "key": "concept_named",
      "verdict": "ok",
      "headline": "The tutor identifies the theorem being proved.",
      "evidence": "The tutor names the theorem (transcribed as 'This is your cell serum' for Thales Theorem) and it is labeled as 'थेल्स प्रमेय' on the problem image.",
      "confidence": 0.85
    },
    {
      "key": "explained_before_solving",
      "verdict": "ok",
      "headline": "The tutor clearly defines what is given, to prove, and the construction before calculating areas.",
      "evidence": "In Frames 2 and 3, given conditions, 'सिद्ध करना है', and construction lines are written and highlighted before calculating areas in Frame 4.",
      "confidence": 0.9
    },
    {
      "key": "concept_checked",
      "verdict": "weak",
      "headline": "Only comprehension check phrases were asked without probing conceptual questions.",
      "evidence": "The tutor asks superficial questions like 'कोई दिक्कत समस्या' and 'Any problem?' throughout the transcript rather than checking conceptual understanding.",
      "confidence": 0.85
    },
    {
      "key": "step_by_step",
      "verdict": "ok",
      "headline": "The theorem is proved step-by-step with visual annotations.",
      "evidence": "Frames 3–8 demonstrate step-by-step progression: constructing perpendiculars, calculating areas of respective triangles, taking ratios, and concluding.",
      "confidence": 0.95
    },
    {
      "key": "opening",
      "verdict": "ok",
      "headline": "The tutor warmly greets the student and confirms language before starting.",
      "evidence": "Transcript opens with 'Hello, Welcome to Filo. What language are you speaking? Hindi or English? Hindi. Okay, okay.'",
      "confidence": 0.95
    }
  ]
}

Frames in order, one every ~45s

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